How much D-glucose is in a 2-μL aliquot of a solution with a concentration of 72 g/L?

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Multiple Choice

How much D-glucose is in a 2-μL aliquot of a solution with a concentration of 72 g/L?

Explanation:
To find the amount of D-glucose in a 2-μL aliquot of a solution with a concentration of 72 g/L, we start by converting the volume from microliters to liters because the concentration is given in grams per liter (g/L). 1. **Convert Volume**: - 2 μL = 2 × 10^-6 L 2. **Calculate the mass of D-glucose**: - Use the formula: \[ \text{mass} = \text{concentration} \times \text{volume} \] Substituting in the values, we have: \[ \text{mass} = 72 \, \text{g/L} \times 2 \times 10^{-6} \, \text{L} \] \[ \text{mass} = 72 \times 2 \times 10^{-6} \, \text{g} \] \[ \text{mass} = 144 \times 10^{-6} \, \text{g} \] \[ \text{mass} = 1.44

To find the amount of D-glucose in a 2-μL aliquot of a solution with a concentration of 72 g/L, we start by converting the volume from microliters to liters because the concentration is given in grams per liter (g/L).

  1. Convert Volume:
  • 2 μL = 2 × 10^-6 L
  1. Calculate the mass of D-glucose:
  • Use the formula:

[

\text{mass} = \text{concentration} \times \text{volume}

]

Substituting in the values, we have:

[

\text{mass} = 72 , \text{g/L} \times 2 \times 10^{-6} , \text{L}

]

[

\text{mass} = 72 \times 2 \times 10^{-6} , \text{g}

]

[

\text{mass} = 144 \times 10^{-6} , \text{g}

]

[

\text{mass} = 1.44

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