If the glucose meter measures 0.67 μmol of electrons, what is the mass of glucose in the sample?

• A. 20 μg
• B. 60 μg
• C. 90 μg
• D. 270 μg

Answer: (B)

To determine the mass of glucose in the sample based on the amount of electrons measured, it is important to first understand the stoichiometry of the redox reaction involved in glucose metabolism. The typical reaction for the oxidation of one molecule of glucose (C6H12O6) involves the transfer of electrons that can be quantified for analysis.

In glycolysis, when one molecule of glucose is oxidized, it releases a set number of electrons. Specifically, one mole of glucose generates a total of 24 moles of electrons per mole of glucose, as it goes through various steps leading to the formation of pyruvate. This can be represented using Faraday's constant to convert the moles of electrons into moles of glucose.

Given that Faraday's constant is approximately 96,485 coulombs per mole of electrons, the measurement of 0.67 μmol of electrons can be converted into moles of glucose. The conversion is structured through the ratio of electrons per mole of glucose oxidized. Thus, we can calculate the moles of glucose:

1. Calculate the moles of electrons: 0.67 μmol = 0.67 x 10^-6 mol.

2. Since glucose oxidation typically involves 24 m