What is the maximum energy of the UV photons generated by a plasma pencil operating at a wavelength of 200 nm?

• A. 7 × 10-16 J
• B. 5 × 10-17 J
• C. 3 × 10-17 J
• D. 1 × 10-18 J

Answer: (D)

To determine the maximum energy of UV photons generated by a plasma pencil operating at a wavelength of 200 nm, we can use the formula that relates the energy of a photon to its wavelength:

[ E = \frac{hc}{\lambda} ]

where:

• ( E ) is the energy of the photon,

• ( h ) is Planck's constant (( 6.626 \times 10^{-34} , \text{Js} )),

• ( c ) is the speed of light (( 3.00 \times 10^{8} , \text{m/s} )),

• ( \lambda ) is the wavelength.

First, we should convert the wavelength from nanometers to meters:

[ 200 , \text{nm} = 200 \times 10^{-9} , \text{m} = 2.00 \times 10^{-7} , \text{m} ]

Now we can substitute the values into the formula:

[ E = \frac{(6.626 \times 10^{-34} , \text{Js})(3.00 \times 10^{8} , \text{